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hi - 1} \] Since \(\phi - 1 = 1/\phi\), this simplifies to: \[ \sum_{n=1}^{\infty} \frac{1}{\phi^{n}} = \frac{1}{1/\phi} = \phi \] Result: \[ \boxed{ \sum_{n=1}^{\infty} \frac{1}{\phi^{n}} = \phi } \] This elegan
