word problems quadratic functions kuta
= x (100 - x) / 2 = (100x - x^2)/2. To maximize A, consider A(x) = (100x - x^2)/2. Find the vertex: Derivative: A'(x) = (100 - 2x)/2 = 0 → 100 - 2x = 0 → x = 50 meters. Find y: y = (100 - 50)/2 = 25 meters. Result: