diffraction and interference problems with solutions
ft(\frac{1 \times 600 \times 10^{-9}}{0.2 \times 10^{-3}}\right) = \sin^{-1}\left( \frac{600 \times 10^{-9}}{0.2 \times 10^{-3}} \right) = \sin^{-1}(0.003) \] Since \( \sin^{-1}(0.003) \approx 0.003\, \text{rad} \), the angle is very small. Fi